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General $N$ black hole puncture initial data:
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General $N$ black hole puncture initial data:
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\begin{equation*}
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\begin{equation*}
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\psi = \sum_{i=1}^N \frac{M_i}{2|\vb*{r}-\vb*{r}_i|} + (\text{regular part}),
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\psi = \sum_{i=1}^N \frac{M_i}{2|\myvec{r}-\myvec{r}_i|} + (\text{regular part}),
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\end{equation*}
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\end{equation*}
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again, if we factor out the conformal factor $\psi$, the remaining conformal metric is regular everywhere.
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again, if we factor out the conformal factor $\psi$, the remaining conformal metric is regular everywhere.
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\end{frame}
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\end{frame}
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@@ -286,6 +286,16 @@
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0 & -\myvec{\xi} & 0
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0 & -\myvec{\xi} & 0
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\end{pmatrix},
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\end{pmatrix},
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\end{equation}
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\end{equation}
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it's very clear that the principal symbol matrix is already symmetric, and thus the system is symmetrically hyperbolic, and well-posed in the $L^2$ sense.
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The eigenvalues are $\lambda_1 = \lambda_2 = \lambda_3 = 0$, $\lambda_4 = -1$ and $\lambda_5 = 1$. The eigenvectors are
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\begin{equation}
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\myvec{e}_1 = \mqty(0\\0\\0\\-1,1), \quad
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\myvec{e}_2 = (0,0,\xi_2,-\xi_1,0)^T, \quad
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\myvec{e}_3 = (0,0,\xi_3,0,-\xi_1)^T, \quad
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\myvec{e}_4 = (0,-1,\xi_1,\xi_2,\xi_3)^T, \quad
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\myvec{e}_5 = (0,1,\xi_1,\xi_2,\xi_3)^T.
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\end{equation}
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\end{frame}
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\end{frame}
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\begin{frame}{Existing first order formulations}
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\begin{frame}{Existing first order formulations}
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