update: auto commit

report.tex

@@ -289,13 +289,17 @@
     it's very clear that the principal symbol matrix is already symmetric, and thus the system is symmetrically hyperbolic, and well-posed in the $L^2$ sense.
 
     The eigenvalues are $\lambda_1 = \lambda_2 = \lambda_3 = 0$, $\lambda_4 = -1$ and $\lambda_5 = 1$. The eigenvectors are
+    {
+      % \fontsize{small}
       \begin{equation}
-      \myvec{e}_1 = \mqty(1\\0\\0\\0\\0),
-      \myvec{e}_2 = \mqty(0\\0\\-\xi_3\\0\\\xi_1),
-      \myvec{e}_3 = \mqty(0\\0\\-\xi_2\\\xi_1\\0),
-      \myvec{e}_4 = \mqty(0\\1\\\xi_1\\\xi_2\\\xi_3),
-      \myvec{e}_5 = \mqty(0\\-1\\\xi_1\\\xi_2\\\xi_3).
+        \myvec{e}_1 = \mqty(1,0,0,0,0)^T,
+        \myvec{e}_2 = \mqty(0,0,-\xi_3,0,\xi_1)^T,
+        \myvec{e}_3 = \mqty(0,0,-\xi_2,\xi_1,0)^T,
+        \myvec{e}_4 = \mqty(0,1,\xi_1,\xi_2,\xi_3)^T,
+        \myvec{e}_5 = \mqty(0,-1,\xi_1,\xi_2,\xi_3)^T.
       \end{equation}
+    }
+    
   \end{frame}
 
   \begin{frame}{Existing first order formulations}